Find the values of (i) sin 18°, (ii) tan 15°
Please koi solve kar do bari mehairbani hogi
No spam please
Answers
Answered by
20
(i)sin 18° = sin A = −1±√5/4
tan 15° = (√3 - 1) / (√3 + 1)
Answered by
0
Answer:
Bro give some more points because all are fast than me not know twomorow
Similar questions