Math, asked by deepak1463, 1 month ago

Find the values of (i) sin 18°, (ii) tan 15°

Please koi solve kar do bari mehairbani hogi


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Answers

Answered by xxsanshkiritixx
20

(i)sin 18° = sin A = −1±√5/4

tan 15° = (√3 - 1) / (√3 + 1)

Answered by SANDHIVA84
0

Answer:

Bro give some more points because all are fast than me not know twomorow

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