find the values of integral 1/x dx
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Answer:
Step-by-step explanation:
Let x = e^u
eu = x
d/dx (eu) = dx/dx
eu * du/dx = 1
du/dx = 1/eu = 1/x
du = 1/x * dx
So now just integrate both sides of 1.e.
(1/x) * dx = du
∫ (1/x) * dx = ∫ du
∫ (1/x) * dx = u + c
Since eu=x
ln( eu ) = ln|x|
u = ln|x|
∫ (1/x) * dx = u + c
∫ (1/x) * dx = ln|x| + c
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