FIND THE VALUes OF k.......
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if (x - 1 ) is the factor , then 1 ia the zeroes of given polynomial.
p(1) = k^2 (1)^2 - 2k (1) -3
0. = k^2 - 2k - 3
0. = k^2 - 3k + k - 3
0. = k (k - 3 ) +1 ( k - 3 )
0. = ( k + 1 ) (k - 3)
( k + 1 ) = 0
k = -1
( k - 3 ) =0
k = 3
p(1) = k^2 (1)^2 - 2k (1) -3
0. = k^2 - 2k - 3
0. = k^2 - 3k + k - 3
0. = k (k - 3 ) +1 ( k - 3 )
0. = ( k + 1 ) (k - 3)
( k + 1 ) = 0
k = -1
( k - 3 ) =0
k = 3
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