Question

find the values of k for each of the following quadratic equations ,so that they have two equal roots:$2x^{2} +kx+3=0$

Answer 1

Answer:

The answer is +or -2$\sqrt{6$

Step-by-step explanation:

As,

2x2 + kx + 3 = 0

Comparing the given equation with ax2 + bx + c = 0, we get,

a = 2, b = k and c = 3

As we know, Discriminant = b2 – 4ac

= (k)^2 – 4(2) (3)

= k^2 – 24

For equal roots, we know,

Discriminant = 0

k^2 – 24 = 0

k^2 = 24

k = ±√24 = ±2√6