Question

find the values of k for each of the following quadratic equations, so that they have two equal roots.
(i) 2x² + kx + 3 = 0
(ii) kx (x - 2) + 6 = 0​

Answer 1

Answer:

k=2 Mark me brainlist and follow me fast

Answer 2

Step-by-step explanation:

If 2x2+kx+3=0 has equal roots, then b2−4ac=0.

Here, a=2,b=k,c=3

x2+kx+3=0b2−4ac=0k2−4(2)(3)=0k2=24k=±24=±26

ii) 

If kx2−2kx+6=0 has equal roots, then b2−4ac=0.

Here, a=k,b=−2k,c=6

kx(x−2)+6=0kx2−2kx+6=04k2−4(k)(6)=04k2−24k=04k(k−6)=0

For k=0, equation is not quadratic.

k=

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