Question

Find the values of k for each of the quadratic equations kx (x – 2) + 6 = 0, so that they have two equal roots.

Answer 1

Step-by-step explanation:

kx(x-2)+6 =0

kx^2 -2kx +6 =0

since roots are equal

discriment = 0

D=b^2-4ac

D= (-2k)^2 -4k(6)

D= 4k^2 -24k=0

= 4k(k-6)=0

4k=0. k-6=0

k=0 or k=6