Question

find the values of k for quadratic equation kx^2+√2-4=0, x=√2 ​

Answer 1

Answer:

kx^2+√2-4=0

k(√2)^2+√2-4=0    (∵x=√2)

2k+√2-4=0

k=(4-√2)/2

k=2-√2/2

 =2-1.414/2

 =2-0.707

 =1.293