Question

find the values of k for the quadratic equation kx(x-2)+6=0,so that it has two equal roots​

Answer 1

Answer:

k=6

Step-by-step explanation:

let delta be 0 [we know if Δ=0 then roots are equal ]
Δ=b²-4ac/2a
eq = kx²-2kx+6 = 0
a=k , b= -2k , c= 6
Δ = (-2k)² - 4(k)(6)/ 2k
 4k² - 24k / 2k
  4k(k-6)/2k
   k- 6 = 0
   k= 6
     
mark me as a brainliest