Math, asked by drishkytz, 2 months ago

find the values of k for which 2/5 is one root of the quadratic equation 5x2-kx+6​

Answers

Answered by sanu21gavit
2

Answer:

let \: x = 2 \div 5 \\  {5x}^{2}  - kx + 6 \\ 5 \times( 2 \div 5)^{2}  - k \times 2 \div 5 + 6 = 0 \\ 5 \times 4 \div 25 - 2k \div 5 + 6 = 0 \\ 4 \div 5 - 2k \div 5 + 6 \times 5 \div 1 \times 5 = 0 \\ 4 - 2k + 30 \div 5 = 0 \\ 4 - 2k + 30 = 0  \times 5 \\ 4 - 2k + 30 = 0 \\ 4 + 30 = 2k \\ 34 \div 2 = k \\ k = 17

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