Question

Find the values of k for which k+12, k-6 and 3 are in gp brainly

Answer 1

if three terms are in gp then
A2/A1 = A3 / A2
so
(k-6)/(k+12) = 3/(k-6) = k^2 - 12 k + 36 = 3k + 36
= k^2 - 15k = 0
k ( k - 15) = 0
k = 0 ,15