Question

Find the values of k for which (k-3)x^2+4(k-3)x+4=0 has two equal roots.

Answer 1

for equal roots
b^2-4ac=0
[4(k-3)]^2-4*4*(k-3)=0
16(k-3)[(k-3)-1]=0
(k-3)(k-4)=0
k=3,4
but k cant be 3
k=4