Find the values of k for which the eqn x2-4x+k=0 has real and distinct real roots
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Answer:
hey. A very easy question. Even you can try your self . Just use the knowledge of quadratic formula.
Step-by-step explanation:
x² - 4x + k =0
here, a=1 b= -4 c =k
now given the roots are real and distinct,
b²-4ac > 0 [ D > 0 AND D = b²-4ac ]
16- 4k > 0 [ substituing the values of a , b ,c ]
16 > 4k
4k < 16
k < 4
This means that all values of k below 4 will give you real and distinct roots
Hope you understand . Please mark my answer as brainliest.
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