Question

find the values of K for which the equation X square + 5 kx + 16 equal to zero has real and equal roots​

Answer 1

Answer:

So, the value of k will be +8/5 and -8/5

Step-by-step explanation:

Given-:

Equation=> x²+5kx+16

To find-:

Value of k=?

Solution-:

As, the equation has equal and real roots.

So, Discriminant will be equal to zero.

So,

b²-4ac=0

where a=1 , b=5k & c= 16

So, By substituting values

we get,

=> (5k)²-4*1*16=0

=>25k²-64=0

=>k²=64/25

=> [k= +8/5, -8/5]✓✓✓✓✓✓