Question

Find the values of k for which the equation x2-2(1+3k)x+7(3+2k)=0is7

Answer 1

it will be helpful for you!!

Answer 2

Answer:

Value of k is 2

Step-by-step explanation:

Given: Quadratic Equation: x² - 2(1+3k)x + 7(3+2k)=0

To find: value of k when x = 7

Put x = 7 in the given quadratic equation, we get

(7)² - 2(1+3k)×7 + 7(3+2k)=0

49 - 14 (1+3k) + 21 + 14k = 0

49 - 14 - 42k + 21 + 14k = 0

56 - 28k = 0

28k = 56

k = $\frac{56}{28}$

k = 2

Therefore, Value of k is 2