Question

Find the values of k for which the equation x2 - 4x + k = 0 has distinct real roots.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

The given quaduric equation is X 2 + 4 x + k = 0 Then find the value ok k.

Here , A = 1 , B = 4 , C = K

As we know that D = b2 - 4ac

Putting the value of A = 1 , B = 4 & C = K

( 4 ) 2 - 4 × 1 × K

= 16 - 4K

• The given equation will have real and district roots. if D > 0 16 - 4 K > 0

4K < 16

K < 16

4

< 4

|| Therefore the value of < 4 ||

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