Question

Find the values of k for which the following equation has real roots4x^2+kx+3=0

Answer 1

Discriminant greater than 0
K2-4.4.3>0
K2>48
K>root 48
K2, I mean k square

Answer 2

If k has real roots:

b^2>4ac

=k^2>4*3*4

=k^2>48

=k>(sqrt)48

If k belongs to any natural number,then it is more than 7 because

k^2=49 which is more than 48 .

Hope this helps