Question

find the values of k for which the following equations have real roots 1. 2x²+kx+3=0 ,2. KX(x-2)+6=0, 3. x²-4kx+k=0, 4. KX(x-2√5)+10=0, 5. KX(x-3)+9=0, 6. 4x²+KX+3=0

Answer 1

1. 2x²+kx+3=0

= 2(1)^2 + k*1 + 3 =0

= 2 + k + 3 = 0

= k = -2-3

= k = -5 ans...

2. KX(x-2)+6=0

= k*1(1-2)+6=0
=k*(-1) + 6=0
= k = -6/-1 = 6 ans

3. x²-4kx+k=0,

= 1 - 4k + k =0
= 1-3k=0
= 1=3k
=k = 1/3 Ans

4. KX(x-2√5)+10=0

= k (1-2root 5 ) +10=0
=k -1root5 +10=0
=k= 1root5 -10Ans


5. KX(x-3)+9=0

= k (1-3)+9
= k - 2 +9
= k - 7
= k = 7ans

6. 4x²+KX+3=0

= 4 + k + 3
= k+7
= k = -7Ans



hope its help u my friend...^_^