Math, asked by suryadeepsinh2982004, 11 months ago

find the values of k for which the given equation has real and equal root. x^2(k + 1) - 2(k - 1) + 1 = 0​

Answers

Answered by rahman786khalilu
5

Answer:

if equal roots

then b^2-4ac=0

4(k-1)^2-4(k+1)(1)=0

(k-1)^2=k+1

k^2-2k+1=k+1

k^2-3k=0

k(k-3)=0

k=0,3


rahman786khalilu: ty for brainliest
Answered by Anonymous
5

Answer:-

Refer the attachment

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