Question

find the values of k for which the given equation has real and equal root. x^2(k + 1) - 2(k - 1) + 1 = 0​

Answer 1

Answer:

if equal roots

then b^2-4ac=0

4(k-1)^2-4(k+1)(1)=0

(k-1)^2=k+1

k^2-2k+1=k+1

k^2-3k=0

k(k-3)=0

k=0,3

Answer 2

Answer:-

Refer the attachment