Math, asked by kingitaat, 1 year ago

find the values of k for which the given equation has real and equal roots k^2x^2-2(k-1)x+4=0

Answers

Answered by Vinayak333
2
According to the question
D=0 or b²- 4ac=0
where a= k²,b= -2(k-1) and c=4
so,
{-2(k-1)}² - 4(k²)(4)=0
4(k²-2k+1) - 16k²=0
4k²-8k+4-16k²=0
-12k²-8k+4=0
multiple by ( - )
12k²+8k-4=0
12k²+12k-4k-4=0
12k(k+1) -4(k+1)=0
12k-1=0 or k+1=0
k=1/12 or k= -1
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

Similar questions