Math, asked by teriya7569, 1 month ago

Find the values of k for which the line x+3y+k and curve y^2=2x+3

Answers

Answered by unique327
0

Correct option is

A

−27/4

2x=k+3y

Putting this in y

2

=6x

y

2

=3(k+3y)⇒y

2

−9y−3k=0

For getting 1 value of y as the line TOUCHES the parabola

We should put the Discriminant of the Quadratic Equation D=0

Hence, 9

2

+12k=0⇒k=

12

−81

=

4

−27

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