Math, asked by iamsaurabhyadav, 10 months ago

Find the values of k for which the pair of linear equations
kx + 3y = k – 2 and 12x + ky = k
has no solution.​

Answers

Answered by psychochori
3

☜☆psychochori☆☞

a1. b1. c1

___ = ____ not = ___

a2. b2. c2.

k. 3

__ = ____

12. k.

now ,

k^2 = 36

k. = √36

k. = 6

3. k - 2

__ = _____

k k

3 not = k - 2

k not = 3 + 2

k not = 5

.•. k = +6 , 6 & not = 5

Thanks...........

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