Question

Find the values of k for which the quad.Eq.9x^2-3kx+k=0 has eaual roots

Answer 1

Answer:

given 9x-3kx+k=0

let a=9, b= -3k, c=k

b2-4ac=0

(-3k)2-4*9*k=0

9k2-36k=0

9k(k-4)=0

9k=0  or k-4=0  hence       k=0   or   k=4