Question

find the values of k for which the quadratic equation 2 x square + kx + 3 is equal to zero has two real equal roots​

Answer 1

Answer:

k = ±2√6  

Step-by-step explanation:

we have to find the values of k for quadratic equations 2x² + kx + 3 = 0 so that they have two equal roots.

We know, the quadratic equation will be equal only when

discriminant, D = b² - 4ac = 0

on comparing 2x² + kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get, a = 2, b = k and c = 3

so Discriminant , D = (k)² - 4(2)(3) = 0

or, k² - 24 = 0

or, k = ± √24 = ±2√6

hence, the value of k = 2√6 or -2√6