Question

Find the values of k for which the quadratic equation 2x^2 +kx+3 has equal roots​

Answer 1

Step-by-step explanation:

2x^2 + kx + 3

we know that,

b^2 - 4ac = 0

(k)^2 - 4(2.3) = 0

k^2 - 24 = 0

k = √24

= 6√2 (ans)

hope this helped you.!❤️

Answer 2

Answer:

$2 \sqrt{6}$

Step-by-step explanation:

2x² + kx + 3 = 0

Using D = b² - 4ac

Here,

b = k

a = 2

c = 3

D = (k)² - 4×2×3 = 0

= k² - 24 = 0

k² = 24

k = √24

k = 2√6