Question

Find the values of k for which the quadratic equation 2x²+kx+3 = 0 has two real roots.

Answer 1

a=2 ,b=k, and D=0 b2-4ac=0

K^2-4×2×3=0
k=+_√24 ok bro

Answer 2

Heya !!




2x² + kx + 3 = 0


Here,


a = 2 , b = k and c = 3





Discriminant ( d ) = 0



b² - 4ac = 0




k² - 4 × 2 × 3 = 0



k² - 24 = 0



k = √24


k = 2√6