Question

Find the values of k for which the quadratic equation (3k+1)x²+2(k+1)x+1=0 has equal roots. Also, find these roots.

Answer 1

Answer:

I really hope this helps...

Step-by-step explanation:

Answer 2

4k (k - 1) = 0

k = 0 or 1

Step-by-step explanation:

(3k+1)x²+2(k+1)x+1=0 has equal roots.

So discriminant is zero.

d = b² - 4ac

a = 3k+1

b = 2(k+1)

c = 1

Substituting to find d:

2²(k+1)² - 4(3k+1)(1) = 0

4(k² + 1 +2k) -4 (3k +1) = 0

4k² + 4 + 8k - 12k -4 = 0  

4k² -4k = 0

4k (k - 1) = 0

If 4k = 0, k = 0.

If k-1 = 0, k = 1