. Find the values of K for which the quadratic
equation (3x+1)x+ 2(x+1)x+] = 0 has equal
roots .
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Step-by-step explanation:
(3x+1)x+2(x+1)x+k=0
3x²+x+2x²+2x+k=0
5x²+3x+k=0
If roots are equal then, b²-4ac=0
Here, a=5, b=3,c=k
b²-4ac=(3)²-4(5)k
9-20k=0
9=20k
9/20=k
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