Question

Find the values of k for which the quadratic equation 3x²+2kx+3 has real roots.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The value of k is ± 3.

Step-by-step-explanation:

The given quadratic equation is 3x² + 2kx + 3 = 0.

We have to find the value k.

Comparing given equation with ax² + bx + c = 0, we get,

• a = 3
• b = 2k
• c = 3

We have given that,

The equation has real & equal roots.

For real and equal roots,

b² - 4ac = 0

⇒ ( 2k )² - 4 * 3 * 3 = 0

⇒ 4k² - 4 * 9 = 0

⇒ 4 ( k² - 9 ) = 0

⇒ k² - 9 = 0

⇒ k² = 9

⇒ k = ± 3

∴ The value of k is ± 3.