Question

Find the values of k for which the quadratic
equation 4x^2 + kx + 1 = 0 if it has equal roots

Answer 1

✫ The value of k is 4 ✫

Step-by-step explanation:

Step-by-step explanation:Given equation: 4x² + kx + 1 =0

To find: Value of k

Required formula:

• For equal roots the quadratic formula is b² - 4ac = 0

Where,

• a = 4
• b = k
• c = 1

Then,

$\\ \mapsto \sf{ {b}^{2} - 4ac = 0} \\ \\ \mapsto \sf{ {k}^{2} - 4(4)(1) = 0} \\ \\ \mapsto \sf{ {k}^{2} - 16 = 0} \\ \\ \mapsto \sf{ {k}^{2} = 16} \\ \\ \mapsto \sf{k = \sqrt{16} } \\ \\ \mapsto \underline {\boxed{\frak{k = 4}}} \: \red{ \bigstar}$

• Hence,the value of k is 4.