Question

Find the values of k for which the quadratic equation 4x²+kx +9=0 has equal roots.

a) 12. b) -12 c) 10. d) both a and b​

Answer 1

Answer:

Solving,

(x−5)−(2x−3)−(x−5)(2x−3)=0

x−2x−5+3−(2x  

2

−13x+15)=0

−2x  

2

+12x−17=0

Now,

D=b  

2

−4ac

D=(12)  

2

−(4)(−2)(−17)

=144−136

=8

D>0

the roots are  real and distinct.

x=  

2(−2)

−12±  

(12)  

2

−(4)(−2)(−17)

​  

 

​  

 

x=  

−4

−12±  

144−136

​  

 

​  

 

x=  

−4

−12±  

8

​  

 

​  

 

x=3±  

2

​  

 

1

​  

Step-by-step explanation:

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