Question

find the values of k for which the quadratic equation 9x2-3kx+k=0 has equal roots.

Answer 1

answer in the picture

Answer 2

Heya user..!!

Here is ur answer..!!

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Answer:  

• k = 4

Step-by-step explanation:

• 9x²-3kx₊k = 0

• By quadratic formula :

• a = 9,  b = -3k , c = k

• b²-4ac =  ( -3k ) ² - 4 ( 9) (k)

            =  9k²- 36k = 0

           = k²-4k=0

          = k ( k - 4 ) = 0

           = k = 0 or k = 4

      ✔✔ Hence, the required value of k is 4 ✅✅.

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I Hope this may help u..!!

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