Math, asked by QwertyPs, 1 year ago

Find the values of k for which the quadratic equation
9x^{2}  - 3kx + k = 0
has equal roots.

Answers

Answered by Anonymous
4

Heya user..!!


Here is ur answer..!!


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Answer:


9x²-3kx₊k = 0


By quadratic formula :


a = 9,  b = -3k , c = k


b²-4ac =  ( -3k ) ² - 4 ( 9) (k)


            =  9k²- 36k = 0


           = k²-4k=0


          = k ( k - 4 ) = 0


           = k = 0 or k = 4


Hence :


       ∴       k=4      




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I Hope this may help u..!!



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Answered by Anonymous
1

Hey mate hope it helps u......

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