Question

Find the values of k for which the quadratic equation x square + 2 root 2 kx + 18 is equals to zero has equal roots

Answer 1

Answer:

k = 3, -3

Step-by-step explanation:

Equation is x² + 2√2kx + 18 = 0

If you compare with ax² + bx + c = 0, we get

a = 1, b = 2√2k , c = 18.

Equation has Equal roots.

∴ D = 0

b² - 4ac = 0

=> (2√2k)² - 4(1)(18) = 0

=> 8k² - 72 = 0

=> k² = 9

=> k = ±3

Therefore, the value of k = ±3

Hope it help!