Question

Find the values of K for which the quadratic equation x^2 - 2kx + 5k = 0 has equal roots

Answer 1

Answer:

k = 5

Step-by-step explanation:

x² - 2kx + 5k = 0

Given that it has equal roots

⇒ b² - 4ac = 0

Solve k:

b² - 4ac = =0

(-2k)² - 4(1)(5k) = 0

4k²  - 20k = 0

k²  - 5k = 0

k(k - 5) = 0

k = 0 or k - 5 = 0

k = 0 or k = 5

Since k = 0 will make the equation not a quadratic equation

⇒ k is rejected

Therefore k = 5

Answer: k = 5

Answer 2

Answer:

Step-by-step explanation

by giving equation

a=1

b=-2k

c=5k

when roots are equal then

D=0

b^2-4ac=0

(-2k)^2-4*1*5k=0

4k^2-20k=0

4k(k-5)=0

either 4k=0

         k=0

or k-5=0

   k=5

I hope it will help you