Find the values of k for which the quadratic
polynomial p(x) = 3x2 + k2x + 2 has - 1 as one of
the zeroes.
Answers
Answered by
3
x=-1
3x^2+ k2x+2 =0
3×-1^2+k×2×-1+2=0
3+-2k +2=0
5-2k=0
-2k=-5
k=5/2
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Answered by
8
Given :-
Quadratic equation
= p(x) = 3x^2 + kx^2 + 2
One of the zeroes is -1
Find :-
Value of K = ?
Solution :-
P(x) = 3x^2 + k^2x + 2
P(-1) = 3(-1)^2 + k^2(-1) + 2
= 3 - k^2 + 2
= 5 - k^2
= -k^2 = -5
( We take 5 to RHS so it becomes -5)
= k = √5
Therefore,
The value of K is √5
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