Math, asked by Anonymous, 6 months ago

Find the values of k for which the quadratic
polynomial p(x) = 3x2 + k2x + 2 has - 1 as one of
the zeroes.​

Answers

Answered by saiyedfazil
3

x=-1

3x^2+ k2x+2 =0

3×-1^2+k×2×-1+2=0

3+-2k +2=0

5-2k=0

-2k=-5

k=5/2

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Answered by Anonymous
8

Given :-

Quadratic equation

= p(x) = 3x^2 + kx^2 + 2

One of the zeroes is -1

Find :-

Value of K = ?

Solution :-

P(x) = 3x^2 + k^2x + 2

P(-1) = 3(-1)^2 + k^2(-1) + 2

= 3 - k^2 + 2

= 5 - k^2

= -k^2 = -5

( We take 5 to RHS so it becomes -5)

= k = √5

Therefore,

The value of K is √5

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