Question

Find the values of k for which the root of the eqation kx²-2kx+6=0 are real and equal.

Answer 1

Answer:

Step-by-step explanation -

for equal and real roots b2 - 4ac =0

(-2k)2- 4(k)(6)=0

4k2 - 24k =0

4k(k-1)=0

k-1=0

k=1