Question

find the values of k for which the roots are real and equal 9x^2 -3x+k=0

Answer 1

Answer:

D=0

b^2-4ac=0

9-4*9*k=0

9-36k=0

9=36k

k=1/4

Step-by-step explanation:

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Answer 2

$\boxed{\huge{\mathfrak{\red{Answer}}}}$

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$\huge{\mathtt{k=4}}$

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Our equation is :

9x² - 3kx + k = 0

Comparing with ax² + bx² + c = 0

We get,

a → 9

b → -3k

c → k

Whenever we are told that the equation has real roots then we use the given formula :

b² = 4 a c

This method can be used effectively to calculate the value of k.

(- 3k )² = 4 ( 9 ) ( k )

9k² = 36k

k² = 4k

k = 4

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