Question

Find the values of k for which the roots of the equation kx2

– 5x + k = 0 are real and equal.​

Answer 1

EXPLANATION.

Quadratic equation.

⇒ kx² - 5x + k = 0.

As we know that,

⇒ D = Discriminant Or b² - 4ac.

For real and equal : D = 0.

⇒ (-5)² - 4(k)(k) = 0.

⇒ 25 - 4k² = 0.

⇒ 25 = 4k².

⇒ k² = 25/4.

⇒ k = √25/4.

⇒ k = 5/2.

                                                                                                                       

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answer 2

Answer:

YOUR Answer Is 5/2...

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