Math, asked by Anonymous, 1 month ago

Find the values of K if the points (0, 0), (2, 3K) and (4K, 6) are collinear.

Answers

Answered by priyasrinithi1984

2

Answer

equate the slopes:

2-0/3k-0=4k-2/6-3k

2/3k=4k-2/6-3k

3k(4k-2) =2(6-3k)

12k^2-6k=12-6k

12k^2=12-6k+6k

12k^2=12

k^2=12/12

k^2=1

k=√1

k=1

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