Question

find the values of k if the roots of the quadratic equation x^2-(k-3) x+k+5=0 are real and equal.


please answer!! ​

Answer 1

Step-by-step explanation:

x^2-k-3)x+k+5=0

x^2-kx-3x+k+5=0

b^2-4ac=0

(k-3)^2-4(1)(k+5)=0

k^2-6k+9-4(k+5)=0

k^2-6k+9-4k-20=0

k^2-10k-11=0

k^2 -11k+k-11=0

k(k-11)+1(k-11)=0

(k-11) (k+1)=0

k=11 or k=-1