Question

find the values of K in the quadratic equation 3 x square - k√3 x + 4 equal to zero has equal roots

Answer 1

Since the equation has equal roots
Discriminent = 0
b^2 - 4ac = 0
${( - k \sqrt{3} )}^{2} - 4(3)(4) = 0$
3k^2 - 48 = 0
3k^2 = 48
k^2 = 16

k = 4


Hope it will help you

Please mark as brainliest if you liked the solution

Answer 2

above equation is 3x^2-k√3x+4
it has equal roots so
$\sqrt{ {b}^{2} - 4ac } = 0 \\ {b {}^{2} - 4ac = 0}^{2} \\ (- k \sqrt{3} ) {}^{2} - 4(3)(4) = 0 \\ 3 {k}^{2} - 48 = 0 \\ 3 {k}^{2} = 48 \\ {k}^{2} = \frac{48}{3} = 16 \\ k = \sqrt{16} = 4$
value of k is 4