find the values of K so that the least value of the expression x^2+2kx+k^2+3k for x=(0,2)
Answers
Answered by
3
Let p(x)= x^2 + 2kx + k^2 + 3K.
Since , for the least value of p(x), x is either equal to 0 or 2 .
→p(0)= p(2)
→ 0+0+k^2 + 3k = 4 + 4k +k^2 + 3K
→ 4+4k= 0
→4 = -4k
→ k = -1 .
Thus , k = -1
Aki456:
Hey... Thanks for the answer but I left some last lkne of the question which says the least value is 4.....i m sry for troubling u can u please now give me the actual answer
The answer is-7,1
Similar questions