Question

Find the values of k so that the quadratic equation x^2-4kx+k=0 has equal roots.

Answer 1

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the value of k is 1/4

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

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Here is your answer.
The quadratic equation is
$x {}^{2} - 4kx + k = 0$
Here
a = 1
b = -4k
c = k

Now
$b {}^{2} - 4ac \\ =( - 4k) {}^{2} - 4 \times 1 \times k \\ = 16k {}^{2} - 4k$
IF ROOTS OF THE EQUATION IS EQUAL THAN
$b {}^{2} - 4ac = 0 \\ 16k {}^{2} - 4k = 0 \\4 k(4k - 1) = 0 \\ k = 0 \: \: \: and \: \: \frac{1}{4}$
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