Question

Find the values of k so that they have two equal root kx(x-2)+6=0

Answer 1

Answer:

Step-by-step explanation:

Kx(x-2)+6=0

Kx²-2kx+6 = 0

A= K, b=-2k , c= 6

B²-4ac = 0

(-2k)²-4(k)(6) = 0

4k²-24k = 0

4k(k-6) = 0

4k = 0 , k-6 = 0

K= 0/4 = 0 , K = 6

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Answer 2

${\boxed{\underline{\tt{\orange{Required \: Answer:-}}}}}$

◉GIVEN:-

Quadratic equation:- kx( x-2)+6=0

(kx^2 - 2kx + 6 = 0)

◉TO FIND:-

Value of K

◉FORMULA USED:-

b^2 - 4ac = 0 (because this quadratic equation have two equal roots)

◉SOLUTIONS:-

Comparing the given equation with general equation ax^2 + bx + c = 0

We get,

a = k

b = -2k

c = 6

$: \longrightarrow \sf{( { - 2k)}^{2} - 4(k)(6) = 0} \\ \\ : \longrightarrow \sf{4 {k}^{2} - 24k = 0 } \\ \\ : \longrightarrow \sf{4k(k - 6) = 0} \\ \\ \sf{ \therefore \pink{ \: k = 0 \: and \: k = 6}}$

HOPE IT HELPS :)✅