Find the values of k so that (x-1) is a factor of k²x²-2kx-3.
Answers
Answered by
17
Let ( x - 1 ) = 0
Then
=> x = 1
Put x = 1 in the given polynomial
P ( x ) = k^2x^2 - 2kx - 3
P ( 1 ) = k^2 ( 1 )^2 - 2k ( 1 ) - 3
=> k^2 - 2k - 3 = 0
=> k^2 - 3k + k + 3 = 0
=> k ( k - 3 ) + 1 ( k + 3 ) = 0
=> ( k + 1 ) ( k - 3 ) = 0
=> ( k + 1 ) = 0 OR ( k - 3 ) = 0
=> k = - 1 OR k = 3
Therefore the value of k is - 1 , 3
Answered by
8
hey!
here is answer
here
x-1=0
hence
x=1
put the. value of. x in polynomial.
hence
it becomes in the form of quadratic equation
hence factorize it
hence
k+1=0
k=-1
or
k-3=0
k=3
hope it helps
thanks
here is answer
here
x-1=0
hence
x=1
put the. value of. x in polynomial.
hence
it becomes in the form of quadratic equation
hence factorize it
hence
k+1=0
k=-1
or
k-3=0
k=3
hope it helps
thanks
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