Question

Find the values of K so that y=kx is secant to curve y=x^2+k.

Answer 1

kx =x²+ 2k

k=x²/x + 2 k

=x²/x+2k/k

= x+k

Answer 2

We knlw that y=kx and y=x^2+2x

So, kx=x^2+2x

x^2+-kx+2x=0

Since this quantity is to be a servant or a line, the discriminant should be greater than 0=D>0

K^2-4k>0

K>4 or k<0

Hence k belong to (- infinity,0)U(4,+ infinity).