Question

find the values of k such that the quadratic equation x2-5x+2(k-5) has equal roots​

Answer 1

Answer:

k=45/8

Step-by-step explanation:

if roots are equal,then

b^2-4ac=0

a=1,b=-5,c=2k-5

(-5)^2-4(1)(2k-5)=0

25-8k+20=0

-8k=-45

k=45/8