Question

find the values of m and n for which X = 2 and X = -3 are solution of equation : 3x^2 -2mx +2n=0​

Answer 1

Step-by-step explanation:

When x=2,

3x^2-2mx+2n=0

3(2)^2-2m(2)+2n=0

3*4-4m+2n=0

12-4m+2n=0

Divide the whole by 2 we get,

6-2m+n=0

6=2m-n ---(Equation 1)

When x=-3,

3(-3)^2-2m(-3)+2n=0

3*9+6m+2n=0

27+6m+2n=0

6m+2n=-27 ---(equation 2)

Multiply the 1st equation by 2,

4m-2n=12

6m+2n=27

10m=39

m=3.9

4(3.9)+2n=12

15.6+2n=12

2n=-3.6

n=-1.8