Math, asked by gokilavani3013, 25 days ago

Find the values of m and n if the following expressions are perfect squares:x⁴-8x³+mx²+nx+16

Answers

Answered by birlasingh373
3

Answer:

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Answered by Anonymous
13

Answer:

24 , 32

Step-by-step explanation:

Given

Find the square root of x^4-8x^3+mx^2+nx+16 and also find the value of m and n

Now we need to find square root of the given expression

So x^2 – 4x + (m – 16)/2

------------------------------------------------------------------

x ^2 x^4 – 8x^3 + mx^2 + nx + 16

2x^2 – 4 x x^4

----------------------------------------------------

- 8x^3 + mx^2

-8x^3 + 16x^4

--------------------------------------------------------------------------------------

2x^2 – 8 x + (m – 16)/2 (m – 16)x^2 + nx + 16

(m – 16)x^2 – 4(m – 16)x + [m – 16/2]^2

Equating the constant term we get

[(m – 16) / 2]^2 = 16

(m – 16)/2 = 4

m – 16 = 8

m = 8 + 16

m = 24

By equating coefficients of x we get

n = - 4(m – 16)

n = -4 (24 – 16)

n = - 4 x 8

n = - 32

So the values of m and n are 24 and - 32

Step-by-step explanation:

@Genius

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