Math, asked by ashwinaswarnimkujur, 1 day ago

Find the values of m and n so that x - c - 1 and x + 2 both are factors of x + (3m + 1) x2 + nx - 18.​

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Answered by harsh351442
4

Answer:

Let f(x) = x 3 + (3m + 1) x 2 + nx − 18. x − 1 = 0 ⇒ x = 1. x − 1 is a factor of f(x). So, remainder = 0. Adding (1) and (2), we get,.

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